解不等式a^2x-1≤a(x-1)

a^2x-1≤a(x-1),
a(a-1)x≤-(a-1),
(1).0<a<1时，a(a-1)<0,x≥-1/a;
(2).a<0或a>1时，a(a-1)>0,x≤-1/a;
(3).a=0时,原不等式成为-1≤0，对任何实数x都成立；
(4).a=1时,原不等式成为x-1≤x-1，对任何实数x都成立.

a^2x-1-ax+a<=0 (a^2-a)x+(a-1)<=0 a(a-1)x+(a-1)<=0 (ax+1)(a-1)<=0 ax+1<=0且a-1>=0或ax+1>=0且a-1<=0 答:x<=-1/a且a>=1或x>=-1/a且a<=1且a不等于0